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0.1x^2-10x=-50.4
We move all terms to the left:
0.1x^2-10x-(-50.4)=0
We add all the numbers together, and all the variables
0.1x^2-10x+50.4=0
a = 0.1; b = -10; c = +50.4;
Δ = b2-4ac
Δ = -102-4·0.1·50.4
Δ = 79.84
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-\sqrt{79.84}}{2*0.1}=\frac{10-\sqrt{79.84}}{0.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+\sqrt{79.84}}{2*0.1}=\frac{10+\sqrt{79.84}}{0.2} $
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